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Hyperjumping calculation (server part)
02-13-2010, 10:40 PM, (This post was last modified: 02-13-2010, 10:50 PM by Neo VII.)
#15
RE: Hyperjumping calculation (server part)
(02-13-2010, 09:57 PM)Morpheus Wrote: The exception to this calculation is Hyperjump in place, as going up and down doesnt make a parabola.

Ahh, okay... in place, like the vertical hyperjump thingy. Took me a second to figure out what that meant.

Could it be written similarly to the way the landing packet will be sent with the right end coordinates on the second ball of the parabola? Or would it be a different packet and animation.
(02-13-2010, 10:19 PM)rajkosto Wrote: its not the same for the key shortcut
since there is no target, you keep going untill you release the key (or you have traveled the maximum distance), then it calculates the falling parabola, and reverses you a bit so it can execute it and you land where you have been before the reversing

Wouldn't the maximum distance of the keybind be the same as the target at the end of the parabola?

Though I get your explanation for the calculation of what happens when you release the key bind.
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Messages In This Thread
RE: Hyperjumping calculation (server part) - by rajkosto - 02-13-2010, 02:11 PM
RE: Hyperjumping calculation (server part) - by rajkosto - 02-13-2010, 04:29 PM
RE: Hyperjumping calculation (server part) - by Neo VII - 02-13-2010, 10:40 PM
RE: Hyperjumping calculation (server part) - by rajkosto - 02-13-2010, 10:19 PM
RE: Hyperjumping calculation (server part) - by rajkosto - 02-13-2010, 11:03 PM

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