MxO Client - Server communication "protocol"

[Neo]

Woah you are great

I dont really understand this before you posted it here ...many thanks for it.
But this means too, we have a big problem to decrypt right? Cause we have to know the secret keys .

The first packet sends a timestamp (backwards like i posted) and the 04 is a algorythm type that is used (found it here : https://www.reverse-engineering.net/view...&sk=t&sd=a ).

0x4 // Type of algorithm or parameter size
0x818102 // Bignum identifier
// RSA-1024 Modulus:
BD 79 35 AE 7B 93 7B 2E 1A 1D F2 75 20 E1 4E 6C
7F 04 2D 7B B2 D9 5B 23 5E F5 72 DF 61 8A A2 2E
EE D6 85 FF 55 E6 CB 83 86 46 6D 35 5E 43 83 3F
B5 4F 70 8D 47 5F 6A A1 3F 4C 1D 47 52 C4 17 AC
5A F3 4B FC 82 9C FF 16 7C 65 43 9B 20 4E 95 9B
8E 33 F3 4F 85 88 22 34 70 A1 F7 A3 B1 73 81 C4
1F A4 93 CE 75 A4 73 E9 A4 17 57 67 5F EA 77 23
53 6A 12 99 D3 BD 0D 88 35 34 4A 9D 21 37 C5 53

0x110102 // Bignum identifier
// Two 1024 bit numbers, or 1 2048 number:
1A 1D 0F A5 FE EE A6 F5 60 29 F3 76 DE 20 F9 D1
FC 76 4A 5C 92 A3 94 3E F8 96 72 26 A9 EA 68 AC
EB AF FD 36 6B 6D 55 26 08 A1 A8 D6 57 6F 63 CA
FB D6 A3 7C 89 52 23 15 30 91 3B 1C B6 0E 6E 85
4B 6B E0 3A B2 09 66 01 6D 99 E8 63 A5 F4 FE 72
45 9C 8A 50 5D 1C ED 34 22 8D A8 72 F1 30 07 AC
6D 17 99 45 B2 9A 65 06 14 B7 8C CF 06 47 79 41
6E 33 52 DA 1F 24 D8 ED 91 CE 53 69 47 7C D6 2B

FD 63 F7 F7 F6 E5 1E 98 81 D1 D8 32 63 E2 29 AF
D5 1B D4 4D 7C B9 0C 8E 2C E7 46 3C D5 FB 0A FA
19 BE 68 6B B1 69 33 F1 6C 1E C0 D9 7A 73 BF 43
88 7A F1 7B 8D E1 6F 15 03 D0 58 7A 6F 4E C3 CC
D2 8E 65 6D 66 86 37 3C F0 78 C9 22 4E D0 32 EA
AB C6 9B BC 7D 0B 7E 30 37 C2 8C F5 98 AD CF BE
3A 20 98 16 F7 98 23 E2 6C D7 60 32 30 06 2B DE
D3 25 63 AC F7 D7 17 5D 93 C2 A5 01 32 38 BE 75

if you edit the pubkey.dat (make it only readable), and fill the 04 with 00, you can see the changes directly in the first packet.

But thats only the one, nothing changed really -.-.